Kmax=hυ-hυ₀
1.when υ>V₀ Kmax=+vr
2.when υ=υ₀ Κmax=0
3.whenυ<υ₀ Κmax=-ve,
no. 3 is impossible.
Thus photoelectrons emitted when υ≥υ₀.
1.when υ>V₀ Kmax=+vr
2.when υ=υ₀ Κmax=0
3.whenυ<υ₀ Κmax=-ve,
no. 3 is impossible.
Thus photoelectrons emitted when υ≥υ₀.
No comments:
Post a Comment